Interactive Linear Algebra
Dan Margalit & Joseph Rabinoff · Georgia Tech · Open textbook
Read §2.1 on vectors and §2.8 on bases as coordinate systems.
Open the sourceVectors as movements; coordinates as a chosen language.
Prerequisites: 02 · Why enlarge the number system?, 04 · Functions and what they forget
Draw a displacement two units right from the origin. Keep the arrow fixed, then replace the horizontal and vertical measuring arrows by b₁=(1,1) and b₂=(1,−1). Predict its new coordinate pair: one of each new arrow adds to (2,0). The MIT change-of-basis excerpt begins at 38:00. [1]
A vector is the displacement, while a coordinate pair records its coefficients in a named basis. In ℝ², addition and scaling are componentwise. The standard basis is e₁=(1,0), e₂=(0,1). The pair b₁=(1,1), b₂=(1,−1) is another basis because its members are independent and span ℝ². For any v in this plane, its b-coordinates (c₁,c₂) are the unique coefficients in the equation:
The letters b₁,b₂ denote the chosen arrows, and c₁,c₂ are scalars. Change the basis, and the coefficients generally change even when v remains fixed. Write the basis alongside a coordinate list; without it, (1,1) can name different vectors.
For v=(4,2) in the standard basis, solve c₁+c₂=4 and c₁−c₂=2. Thus c₁=3 and c₂=1, and 3b₁+b₂=(4,2). The same arrow has standard coordinates (4,2) and b-coordinates (3,1). For (2,0), its b-coordinates are (1,1).
| Fixed arrow | Standard coordinates | b-basis coefficients |
|---|---|---|
| v | (2,0) | (1,1): b₁+b₂ |
| w | (4,2) | (3,1): 3b₁+b₂ |
Counterexample to “any two arrows make a basis”: (1,0) and (2,0) are distinct but parallel. No combination of them gives (0,1), so there is no two-coordinate description of that arrow using this pair. A proposed change of basis must actually be invertible.
Keep v=(2,0) fixed. First predict its b-coordinates, then add b₁ and b₂ on paper and compare the result with the diagram and table.
Can an arrow have coordinate (1,1) in one basis and (2,0) in another?
With b₁=(1,1) and b₂=(1,−1), what is the first b-coordinate of v=(6,−2)?
Which remains unchanged under an invertible change of basis?
Describe v=(4,2) in the standard and b-bases, verify both combinations, and explain why two parallel arrows cannot replace b₁,b₂.
Dan Margalit & Joseph Rabinoff · Georgia Tech · Open textbook
Read §2.1 on vectors and §2.8 on bases as coordinate systems.
Open the sourceDeisenroth, Faisal & Ong · Freely readable textbook
Read §2.4 on vector spaces, printed p.35 onward, as a second pass.
Open the sourceGilbert Strang · MIT OpenCourseWare · Lecture · 50 min
Start at 35:00. Watch the short core 38:00–42:00; then the longer passage 35:00–50:00. The full 50-minute lecture is available from the same link.
Open the source