Book of Proof, third edition
Richard Hammack · Free textbook
Read §14.1, printed pp.269–270 / PDF pp.281–282, for finite matching; use §1.1 only as notation repair.
Open the sourceA quantity, a symbol, a position — or a pattern of relationships?
Prerequisites: None
Put five stones beside five taps. Predict whether changing their spacing changes how many there are. Pair each stone with one tap; every object has exactly one partner and nothing is left over. The pairing survives the rearrangement. Now remove one tap: one stone has no partner. The short MIT passage starts with this matching test. [1]
For finite sets A and B, a bijection is a matching that gives every member of A exactly one distinct member of B and uses every member of B. They then have equal cardinality, written |A|=|B|. The written mark “5” is a numeral for a number; it is not five stones. Counting also supplies an order: fifth names a position, not the size of the whole collection.
The vertical bars mean the finite number of members; A and B name the collections. A successor rule gives another view of natural numbers: start at zero and apply “next” repeatedly. Here S(S(S(0))) names three. This course includes zero among the natural numbers. A rule or encoding is a way to represent the number, not a claim that physical objects are made of symbols.
Let A={red,blue,green} and B={4,7,9}. Match red→4, blue→7, green→9. This uses all three on each side, so both cardinalities are three. Replacing the label 9 by a square object does not change the count. The numeral 3 and the binary numeral 11 name that same number in different notations.
| Collection | Partners | Left over |
|---|---|---|
| 5 stones, 5 taps | 5 | 0 |
| 5 stones, 4 taps | 4 | 1 stone |
| 0 stones, 0 taps | 0 | 0 |
Counterexample to “equal cardinality means identical appearance”: {red,blue,green} and {4,7,9} have no matching labels or materials, yet the displayed bijection proves equal size. Conversely, “11” is a numeral whose value depends on its base; in binary it is three, not eleven.
Predict the result for 5 versus 5, 5 versus 4, and 0 versus 0 before drawing pairs. Rearrange without adding or removing objects; count unmatched objects afterward.
Can two collections be equally numerous even when no object in one resembles anything in the other?
Which change leaves five stones with the same cardinality?
A={red,blue,green} and B={4,7,9}. How many pairs does a bijection use?
Match two differently labeled collections of four objects. Explain why the match proves equal cardinality but neither the labels nor an ordinal position define that cardinality.
Richard Hammack · Free textbook
Read §14.1, printed pp.269–270 / PDF pp.281–282, for finite matching; use §1.1 only as notation repair.
Open the sourceOpenStax · Open textbook
Use chapter 1 whole numbers, counting and notation if needed.
Open the sourceMIT OpenCourseWare · Lecture · 85 min
Start at 2:30. Watch the short core 2:30–4:45; then the longer passage 2:30–22:30. The full 85-minute lecture is available from the same link.
Open the source